arange stack regression test (#17250)

* simple failing test

* commend out stack

* a little smaller

* work
This commit is contained in:
qazal
2026-07-28 20:00:22 +09:00
committed by GitHub
parent e3b3eea1e2
commit 05e4727feb
3 changed files with 9 additions and 1 deletions
+6
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@@ -19,6 +19,12 @@ class TestArange(unittest.TestCase):
self.assertLess(self._get_flops(Tensor.arange(256).clone(), np.arange(256)), 256*4)
self.assertLess(self._get_flops(Tensor.arange(2560).clone(), np.arange(2560)), 2560*4)
def test_cat_complexity(self):
x = Tensor.arange(2**10) + Tensor.empty((), dtype=dtypes.uint32)
out = x.cat(x).cat(Tensor.empty(1, dtype=dtypes.uint32))
linear = compile_linear(out.schedule_linear())
self.assertLessEqual(estimate_uop(linear.src[-1]).ops, out.numel()*20)
@unittest.skipIf(Device.DEFAULT == "CL", "flaky in CI")
def test_arange_cumsum(self):
np.testing.assert_equal(Tensor.arange(513).cumsum(0).numpy(), np.arange(513).cumsum())
+1
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@@ -123,6 +123,7 @@ class TestUOpsStats(unittest.TestCase):
# NOTE; ops also include indexing ops
assert expected_ops <= ops and ops <= expected_ops * 2
@unittest.expectedFailure
def test_cat_equal_pieces(self):
# concatenating equal-size pieces lowers to STACK: pure data movement, no arithmetic
equal = [Tensor.empty(256, 128) for _ in range(4)]
+2 -1
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@@ -719,7 +719,8 @@ class OpMixin(ElementwiseMixin, ReduceMixin):
dim = self._resolve_dim(dim)
for arg in args: assert arg.ndim==self.ndim and all(ti==ai for i,(ti,ai) in enumerate(zip(self.shape, arg.shape)) if i!=dim)
tensors = [self, *args]
if all(t.shape[dim] == self.shape[dim] for t in args): return self.stack(*args, dim=dim).flatten(dim, dim+1)
# TODO: enable this
#if all(t.shape[dim] == self.shape[dim] for t in args): return self.stack(*args, dim=dim).flatten(dim, dim+1)
dim_cumsum = list(itertools.accumulate([t.shape[dim] for t in tensors], initial=0))
padded = [t.pad(tuple((dim_cumsum[i], dim_cumsum[-1]-dim_cumsum[i+1]) if j==dim else None for j in range(t.ndim))) for i,t in enumerate(tensors)]
return padded[0].usum(*padded[1:])